Search Coverage: Programming Language Gate 2014 Problem Solution

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Consider the function func shown below: int func(int num) { int count = 0; while (num) { count++; num greaterThan greaterThan= 1; } ... Consider the following function. double f(double x){ if( abs(x*x - 3) lessThan 0.01) return x; else return f(x/2 + 1.5/x); } Give a value ... Suppose n and p are unsigned int variables in a C program. We wish to set p to nC3. If n is large, which one of the following ... Consider the C function given below. int f(int j) { static int i = 50; int k; if (i == j) { printf("something"); k = f(i); return 0; } else return 0; } ... The minimum number of arithmetic operations required to evaluate the polynomial P(X)=X5+4X3+6X+5 for a given value of X, ... Let A be a square matrix of size n x n. Consider the following program. What is the expected output? C = 100 for(i=0; i lessThan n; ...

Consider the following program main() { int i; int*pi = &i; scanf("%d",pi); printf("%d\n", i+5); } Which one of the following statements ... Consider the following C code segment. int a, b, c = 0; void prtFun(void); main() { static int a = 1; /* Line 1 */ prtFun(); a += 1; ... What will be the output of the following C program segment? char inChar = 'A'; switch ( inChar ) { case 'A' : printf ("Choice A \n"); ...

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Programming Language GATE-2014 Problem Solution

369 views • Live Report

Consider the function func shown below: int func(int num) { int count = 0; while (num) { count++; num greaterThan greaterThan= 1; } ...

Programming Language GATE-2014 Problem Solution

764 views • Live Report

Consider the following function. double f(double x){ if( abs(x*x - 3) lessThan 0.01) return x; else return f(x/2 + 1.5/x); } Give a value ...

Programming Language GATE-2014 Problem Solution

1,180 views • Live Report

Suppose n and p are unsigned int variables in a C program. We wish to set p to nC3. If n is large, which one of the following ...

Programming Language GATE-2014 Problem Solution

325 views • Live Report

Consider the C function given below. int f(int j) { static int i = 50; int k; if (i == j) { printf("something"); k = f(i); return 0; } else return 0; } ...

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Last Updated: June 16, 2026

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