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You're literally one click away from a better setup — grab it now! As an Amazon Associate I earn ... In this video, we create a short and efficient solution to the The series (1**1) + (2**2) + (3**3) + ... + (10**10) = 10405071317. Find the last ten digits of the series (1**1) + (2**2) + (3**3) + . Hey Nerd boys and girls! Let's have a go at challenge 30, and see how many numbers are equal to the sum of their own digits ... Not too difficult of a problem but the 1 not counting threw me off for a little while. Please don't forget to like if you liked the video ... Pretty simple problem here, not much to discuss. Please don't forget to like if you liked the video and if you want to see ...

Problem 5: Smallest Multiple Problem 6: Sum Square Difference Problem 7: 10 001st Prime. Really quick and easy video showing my solution for problem 16 of the

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Last Updated: June 14, 2026

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Code Review: Project Euler # 48 Self powers in Python

Code Review: Project Euler # 48 Self powers in Python

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You're literally one click away from a better setup — grab it now! As an Amazon Associate I earn ...

Project Euler 48: A short and quick solution with Python

Project Euler 48: A short and quick solution with Python

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In this video, we create a short and efficient solution to the

Project Euler 048 - Self Powers

Project Euler 048 - Self Powers

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The series (1**1) + (2**2) + (3**3) + ... + (10**10) = 10405071317. Find the last ten digits of the series (1**1) + (2**2) + (3**3) + .

48 - Solving Euler #1

48 - Solving Euler #1

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